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Mathematics 10 Online
OpenStudy (anonymous):

Factor each for the differences of two squares

OpenStudy (anonymous):

do you mean x<2=4x+21?

OpenStudy (anonymous):

(x+3).(x-7)=0->x=7 and x=-3

OpenStudy (anonymous):

-7 and 3

OpenStudy (anonymous):

Thanks. How exactly would I know how to solve? Is there a way or method that would help me to remember?

OpenStudy (anonymous):

Would I factor then, find the sum?

OpenStudy (anonymous):

-21=-7.3 and 7-3=-(-4)

OpenStudy (anonymous):

Oh okay. So it's similar to the trial and error method. Thanks

OpenStudy (p0sitr0n):

\[x1,2 =( -b \pm \sqrt{b^2 -4ac})/2a\], where a=-1, b=4, c=21

OpenStudy (p0sitr0n):

or you could use the sum product method as product of the 2 terms = 21 and sum of the two terms =-4.

OpenStudy (anonymous):

sum of two therms is 4 not -4

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