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Factor each for the differences of two squares
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do you mean x<2=4x+21?
(x+3).(x-7)=0->x=7 and x=-3
-7 and 3
Thanks. How exactly would I know how to solve? Is there a way or method that would help me to remember?
Would I factor then, find the sum?
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-21=-7.3 and 7-3=-(-4)
Oh okay. So it's similar to the trial and error method. Thanks
\[x1,2 =( -b \pm \sqrt{b^2 -4ac})/2a\], where a=-1, b=4, c=21
or you could use the sum product method as product of the 2 terms = 21 and sum of the two terms =-4.
sum of two therms is 4 not -4
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