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Given: \[\LARGE \log_5x>\log_{25}(3x-2)\] Attempted: \[\LARGE \log_5x>\frac12 \cdot \log_5(3x-2)\] \[\LARGE 2\cdot \log_5x>\log_5(3x-2)\] \[\LARGE 2 >{\log_5(3x-2)\over \log_5x}\] \[\LARGE 2 >\log_x(3x-2)\] \[\LARGE 2 >\text{Stuck!}\] Anyway... Multiple choices are: \[\LARGE A) \quad x\in (2,\infty )\] \[\LARGE B) \quad x\in (1,4 )\] \[\LARGE C) \quad x\in \left(\frac23,1 \right) \cup (2,\infty)\] \[\LARGE D) \quad x\in \left(\frac23,1 \right) \cup (1,\infty)\]
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