What are the x-intercept(s) of the graph of y − x2 = −11x + 24? (4 points)
(−3, 0) and (8, 0)
(3, 0) and (−8, 0)
(−3, 0) and (−8, 0)
(3, 0) and (8, 0)

Question

What are the x-intercept(s) of the graph of y − x2 = −11x + 24?  (4 points)
(−3, 0) and (8, 0)
(3, 0) and (−8, 0)
(−3, 0) and (−8, 0)
(3, 0) and (8, 0)

anonymous · Answer

please!!!!!

anonymous · Answer

ASAP

sburchette · Answer

adding x^2 to both sides we get$$y=x^2-11x+24$$To find the x-intercepts of a function, substitute 0 for y and then solve for x.  Because it is a quadratic function, you can expect 2 intercepts unless they are complex roots.  Substituting 0 for y we have$$0=x^2-11x+24$$ Now we need to factor the right side.  We need to find two values such that when they are multiplied they equal 24 and when they are added they equal -11.  -8*-3=24 and -8-3=-11 so we know that it will factor into $$0=(x-3)(x-8)$$Now we can set each factor equal to zero to obtain the solutions which are$$x=3,x=8 $$

anonymous · Answer

also I need help with this one 
What are the solutions of 6x2 − x − 15 = 0?  (4 points)
x = , x = −3
x = −, x = 3
x = , x = −
x = −, x =