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Mathematics 13 Online
OpenStudy (anonymous):

Is the following relation a function? see attachment

OpenStudy (anonymous):

OpenStudy (anonymous):

no because 0 and 4 produce the same result

OpenStudy (anonymous):

Yes it is. Moreover it is many-one type function.

OpenStudy (ash2326):

@thomasj it's a function A relation is a function if for each x there is only one y so it's a function

OpenStudy (anonymous):

yes it is a function. many to one type

OpenStudy (anonymous):

Eg of {not a function} is that for one value of x, you have more than one value of y.

OpenStudy (anonymous):

no because 0 and 4 produce the same result

OpenStudy (anonymous):

no because 0 and 4 produce the same result

OpenStudy (anonymous):

no because 0 and 4 produce the same result

OpenStudy (anonymous):

@thomasj , have a check at your basics again :)

OpenStudy (anonymous):

@thomasj what is wrong with the x^2? It is a function but not the x^(1/2) unless we restrict it to some particular range..

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