Question

how to convert (-1,squareroot 3) to polar where r is negative

Answer 1

\(r\) is a length, so it is not negative

Answer 2

\[r=\sqrt{a^2+b^2}=\sqrt{1^2+\sqrt{3}^2}=\sqrt{1+3}=\sqrt{4}=2\]
\[\theta =\frac{4\pi}{3}\]

Answer 3

r has to be negative

Answer 4

so it can flip when graphing it

Answer 5

then make is \(-2\) and change the sign inside

Answer 6

the answer is (-2,5pi/3)

Answer 7

i just dont know how to find the angle once i find r