The second angle of a triangle is 25 more than twice the measure of the first angle. The third angle of a triangle is 15 degrees more than half the measure of the first angle. Find the measure of each angle. Can someone please show me a drawing of what this would look like?
We're going to represent the first angle with "a". Since the second and third angles are defined by a, we can also represent these angles using this variable. the second angle = 2a+25 the third angle = a/2+15 since the total number of degrees in a triangle is 180 a+2a+25+a/2+15=180 combine like terms 3a+a/2+40=180 3a+a/2=140 (we subtracted 40 from both sides) 6a+a=280 (we multiplied both sides by 2 to remove the /2 from the second "a") 7a=280 a=40 (we divided both sides by 7 to remove the coefficient) now that we have found a, we can define the other angles with this value angle 2 = 2(40)+25 = 80+25 = 105 angle 3 = 40/2+15 = 20+15 = 35 we can check our work by adding all the angles together 40+105+35 = 40+140 = 180 this triangle would look something like this |dw:1335144127068:dw|
okay thanks
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