OpenStudy (anonymous):

There are 200 amino acids, and 6 nucleotides available 6^3 = 216 [need 3 codons to code for the amino acids] the question asks: how many codons will be redundant?

5 years ago
OpenStudy (blues):

You need 3 bases to code for an amino acid, not 3 codons. A codon is 3 bases. You have 216 possibilities and you need to code for 200 different amino acids. So how many coding possibilities will be 'left over' once all 200 amino acids have codons assigned to them?

5 years ago
OpenStudy (anonymous):

16? but according the wobble, wouldnt there be more redundant?

5 years ago
OpenStudy (blues):

Not in this little to system. I think 16 is correct. Mind you, this is hardly a question you'd ever have to answer in real science.

5 years ago
OpenStudy (anonymous):

and do i need to take account in the stop codons too?

5 years ago
OpenStudy (blues):

Probably a good idea. Technically you only need one...

5 years ago
OpenStudy (anonymous):

ok thanks so much

5 years ago
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