Question

A scientist uses a scale Y for measuring temperature. In this scale, pure water melts at 10oY and boils at 130oY at standard atmospheric pressure. The scientist measures the temperature at which sodium melts to be 127oY. Express this temperature in degrees celcius

Answer 1

130oY------> 100oC
10oY -------->0oc
Therefore
1unit of oY=100/120=5/6 oC

127oY= 130oY - 3oY= 100oC- 3*5/6oY = (100-2.5)oY=97.5oC

Final Ans 97.5oC

Answer 2

@shivam_bhalla pls explain this line 127oY= 130oY - 3oY= 100oC- 3*5/6oY = (100-2.5)oY=97.5oC

Answer 3

where u ve 3*5/6oY

Answer 4

i got it now

Answer 5

I am not sure whether this is right. Only applying logic.

127oY= 130oY - 3oY

WKT 130oY = 100oC

And WKT, 1oY=5/6oC
Therefore, 3oY = 3 *(5/6)oC = 2.5 oC.

Finally we get,

127oY= 100oC-2.5oC=97.5oC

I still say that somebody verify this because I am not sure.

Answer 6

it is right..