A 1.00-nF capacitor initially charged to 30.0 V and a 2.00-nF capacitor charged to 40.0 V are connected to each other with the negative plate of each connected to the negative plate of the other. What is the final charge on the 2.00-nF capacitor?

Question

anonymous · Answer

if any one know the equation please tell me :( i don't want the final solution if u don't know

anonymous · Answer

when the two capacitors are joined ,charge will flow from the one at higher potential(40V) to the on at lower potential until both are at same potential. the charge lost by 2nF CAPACITOR IEQUAL TO THE CHARGE GAINED BY THE 1NfCApacitor because there is no other way for the charge to escape

anonymous · Answer

|dw:1335193557386:dw|