Question

How would you define the slope of the line defined as :

x=3+2t
y=2-t
z=1+5t

Answer 1

WHAT *gasp* you are asking a question!?

Answer 2

(x',y',z') this is the slope

Answer 3

im trying to build my smartscore in asking :)

Answer 4

lol

Answer 5

slope of a tangent plane, dont know myself, good question

Answer 6

not the plane itself; just the line in the plane

Answer 7

(2,-1,5)

Answer 8

that is not a slope, that is a vector

Answer 9

it is a derivative of parametric curve

Answer 10

and it is a vector of the line; it is not the slope of the line ... think more along the "lines" of directional derivatives

Answer 11

if you know how to do, why are you asking

Answer 12

slope in 3d.....:)

Answer 13

its not a crime to propose ideas for consideration

Answer 14

:) slope in 3d yes

Answer 15

you got the 3 slopes in that vector. For each axis.... just pick one you like more

Answer 16

thats wont give me the slope in the direction of the line tho

Answer 17

you could look at it as z=f(x,y) and define the slope for any direction in the x,y plane as the directional derivative of f(x,y)

Answer 18

what do you understand by slope?

Answer 19

begin, yes, but spose we dont know how to determine a directional derivative; what would be the next best thing to define the slope of a 3d line?

Answer 20

i'm thinking perhaps we can take the gradaient of the plane defined by that line

Answer 21

Yout line = (3,2,1) +t(2,-1,5)

Answer 22

this is only x axis, you missing the other two