Question

Write an equation of a line in slope intercept form that is parallel to y = 3x+6 and passes through the point (-10, 2.5)

Answer 1

help help help help

Answer 2

firstly - what do you think is the slope of the line y = 3x + 6?

Answer 3

3

Answer 4

correct

Answer 5

y=mx+b
m is 3 because the line you are looking for is parallel
you have your x and y coordinates, so plug them in and solve for b.

Answer 6

so the line paralle to this must have the same slope (i.e. 3) which means its equation must be:

y = 3x + c

where c is some constant

Answer 7

now you just need to put in the point given to you to find c

Answer 8

?
so how do i solve

Answer 9

you are given that x=-10 when y=2.5 on this line

Answer 10

you've been given your x and y in the form of (-10,2.5)

Answer 11

so just substitute x=-10, y=2.5 into y = 3x + c to find c

Answer 12

so do i plug those in to y=3x+b

Answer 13

why is it c not b?

Answer 14

correct

Answer 15

you can use any symbol for the constant, Chris used b I used c - it doesn't matter

Answer 16

it's just a different variable. they both represent the y-intercept

Answer 17

uhm i got 32.5 = b is that correct

Answer 18

yup

Answer 19

that's what I got

Answer 20

okaay

Answer 21

Write an equation of a line in slope intercept form that is perpendicular to y = -4x -2 and passes through the point (-16, -11). how would i do this

Answer 22

or what else do i do for the previous problem

Answer 23

you have solved the previous problem - please post new questions to the left.

Answer 24

for the previous problem, you need to get your new equation in the general form of y=mx+b. You need to supply the values for m and b, and leave x and y as variables.

Answer 25

help me with the second one

Answer 26

you have to submit that one as a separate problem after you close this one out.

Answer 27

i did