Question

\log (x) = -0.123, what does x equal?

Answer 1

The important thing to know here is that e^x and log(x) are "Inverse functions"
That's fancy-talk for "they undo each other."
So think about an equation like
2x = 10
To get x by itself, I have to divide by 2. That's because dividing by 2 and multiplying by 2 are inverse functions. They "undo" each other.
+3 and -3 "undo" each other.
Squared and square root undo each other.

Answer 2

So your algebra looks like:
log(x) = -0.123
\[e^{\log(x)} = e^{-0.123}\]

Answer 3

Oh, I made a simple mistake, but it's an important one.
Whatever the base is for my log, that's the thing I want to raise my power for. Log(x) assumes log base 10, so I'm going to do:
\[10^{\log(x)} = 10^{-0.123}\]

Answer 4

(If it was ln(x), then that would be log base e, so I'd do e^ln(x))

Answer 5

so all you have to find is 10^-0.123?

Answer 6

Yeah =D Cool, right?

Answer 7

THANK YOU! you were very helpful :)

Answer 8

My pleasure =)