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Solve for x and y. x = 6; y = 3√13 x = 2√6; y = 6√2 x = 6; y = 2√6 x = √78; y = 6 Question is below
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It's my last question!
I'd start by writing out the quadratic equation for the three different triangles in the picture, then solve for x or y and set them equal to each other.
I had already set it all up and I got C. But, i'm not quite sure if i'm precise.
x = 6; y = 2√6 That would be it right?
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Check it by plugging it back into the quadratic equation for the triangle PSQ -- a^2 + b^2 = c^2.
B!
Do those values also work for triangle PQR (I haven't calculated it).
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