Question

find the monic quadratic polynomial that crosses the y axis at (0,-6) and the x axis at (3,0)

Answer 1

You know that 3 is a root so can you just do
(x - 3)(x - a) = x^2 - ax - 3x + 3a

Then when x = 0, y = -6
3a = - 6
a = -2

so x^2 -x -6

Answer 2

THANK YOU VERY MUCH!

Answer 3

umm how does finding a=-2 help you deduce x^2 -x -6

Answer 4

oh dw i get it now haha

Answer 5

Sub the values into x^2 - ax - 3x + 3a
x^2 + 2x - 3x +3(-2)
= x^2 -x -6

Answer 6

Oh ok. :)