Question

given SEC= 8/3, find the 6 trigonometric ratios for beta

Answer 1

If the secant is 8/3, the cosine is the inverse of the secant: COS = 1/SEC
COS = 3/8
Is this what you're asking?

Answer 2

\[\sec(\beta)=\frac{8}{3}\]
\[\cos(\beta)=\frac{3}{8}\] the others depend on what quadrant you are in

Answer 3

we can pretend we are in quadrant one and solve those

Answer 4

For the sine you can use:
\[\sin^2\beta+\cos^2\beta=1\]
But, as satellite73 said, for the sign of the sine the quadrant is important.

Answer 5

Since the cosine is positive, the quadrants are limited 1 and 4. So, we can do what satellite73 said and pretend we are in quadrant 1.

Answer 6

that's actully wrong.

Answer 7

How so?