the following equaton has three solutions. look for the GCF then use the quadratic formula to find all solutions. 3x^3+1x^2+1x=0

Question

the following equaton has three solutions. look for the GCF then use the quadratic formula to find all solutions.      3x^3+1x^2+1x=0

anonymous · Answer

x is the gcf
so, x (3x^2+x=1)=0
can you do it from here?

anonymous · Answer

i factored out the x but now i dont know what to do with the quadratic formula

anonymous · Answer

sorry, there was a typo

x (3x^2+x+1)=0

anonymous · Answer

so i use the 3x^2+x+1 for the quadratic formula?

anonymous · Answer

look, if x=0, then the equation is true. so that is one solution.
Yes then use the qudratic formula to find the other two solutions

anonymous · Answer

will you be ok now?

anonymous · Answer

i got $$(-1+\sqrt{11})/2$$

anonymous · Answer

but its telling  that not correct

anonymous · Answer

hold on while i work it out

anonymous · Answer

you did the sutbraction wrong under the rad

anonymous · Answer

and it is -1+ or - the rad/2

anonymous · Answer

still there?

anonymous · Answer

yes i dont understand

anonymous · Answer

-1 +-rad(1-4*3*1)/2*3
-1+-rad (-11)/6