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the following equaton has three solutions. look for the GCF then use the quadratic formula to find all solutions. 3x^3+1x^2+1x=0
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x is the gcf so, x (3x^2+x=1)=0 can you do it from here?
i factored out the x but now i dont know what to do with the quadratic formula
sorry, there was a typo x (3x^2+x+1)=0
so i use the 3x^2+x+1 for the quadratic formula?
look, if x=0, then the equation is true. so that is one solution. Yes then use the qudratic formula to find the other two solutions
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will you be ok now?
i got \[(-1+\sqrt{11})/2\]
but its telling that not correct
hold on while i work it out
you did the sutbraction wrong under the rad
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and it is -1+ or - the rad/2
still there?
yes i dont understand
-1 +-rad(1-4*3*1)/2*3 -1+-rad (-11)/6
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