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find the general antiderivative of f(x)=(e^(sinx))(cosx)
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Let u = sinx, du = cosxdx Then,\[\int\limits e^udu = e^uu \prime\]
What is the mark after the u?
To calculate \[\int e^{\sin x}\cos x dx\] Make u = sin x, and du = cos x dx
Then: \[\int e^u du=e^u+\text{constant}\]
So your answer should be \[e^{\sin x}+\text{constant}\] The constant is important, because the question is asking for the general antiderivative.
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