Question

Let f(x)=2x^2 +4x-6.
Express f(x) in the form f(x)=2(x-h)^2 +k.

Answer 1

well... if
\[\LARGE f(x)=2x^2+4x-6\]
we can add +8-8 because its value is 0 so it doesn't change the value of the function
... we have:
\[\LARGE f(x)=2x^2+4x-6+8-8\]
\[\LARGE f(x)=2x^2+4x+2-8\]
now we take 2 in common ...
\[\LARGE f(x)=2(x^2+2x+1)-8\]
\[\LARGE f(x)=2(x+1)^2- 8\]

but your question seems to ask about
(x-h)^2
only if we write this like:
\[\LARGE f(x)=2(x-(-1))^2- 8\]

what do you think? :(

Answer 2

and there is -8 not +8 lol I seem to messed it up !

Answer 3

+(-8) lol

Answer 4

Hi Kreshnik, yes the answer's correct. The power is over the bracket of (x-h). I understand how you got it. Thank you!

Answer 5

My pleasure xD