Question

48x^2y+20xz+12xy+5z

Answer 1

factor please and thank you. this one all i no is that you seperate them in to two parts and then factor but i dont get how to factor when theres so many different letters

Answer 2

(4x+1)(12xy+5z)

Answer 3

how do u get that?

Answer 4

someone please explain to me how he got that anwser?

Answer 5

Group the terms that can be divided by 5, and the group that can be divided by 12
48x^2y + 12xy+20xz+5z now look at the first two term and remove what is common to both terms: 12xy(4x+1) do the same to the last two 5z(4x+1)
We now have 12xy(4x+1) + 5z(4x+1) Now what do we have in common with these, as you may have guessed it is (4x+1) It is contained in both of them, remove it
(4x+1)(12xy+5z). With lots of practice, you will soon develop a knack for it.