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25^(x2)(5^(7x))=625
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what about it?
i have to solve the exponential equation... the solutions.
25 squared is equal to 625. That means (x2)(5^(7x)) = 2
the question is asking you to find x... so that 5 to a poweris equal to 625 simplify the some terms with 5 as the base 25 = 5^2 and 625 = 5^4 then \[(5^2)^{x^2} \times (5)^{7x} = 5^4\] simplify using the power laws \[5^{2x^2} \times5^{7x} = 5^4\] when multiplying add the powers \[5^{2x^2 + 7x} = 5^4\] equate the powers and solve for x \[2x^2 + 7x = 4\] or \[2x^2 + 7x - 4= 0\] solve the quadratic (2x -1)(x+4)=0 x = 1/2 or -4 then with value of x, found above, will result in 625 when substituted into the original equation
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