Question

log(3x+2)+log(x-1)=2 how to solve for x?

Answer 1

(x-1 should be >0 and 3x+2 > 0 for logarithm to be defined)
log((3x+2)(x-1))=2
log((3x^2-3x+2x-2))=2
taking out log
3x^2-x-2=10^2
3x^2-x-2=100
3x^2-x-102=0
facotring these shall give you
(x-6)(3x+17)=0
x=6 or x=-17/3

From the first sentence, we can eliminate -17/3

making x=6 is the right answer

Answer 2

Thank you!