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Mathematics 8 Online
OpenStudy (anonymous):

A function f: X → Y is bijective, where X and Y are finite sets. The number of possible relations from X to Y is 512. If X and Y have exactly one element in common, then what is the number of elements in X ∪ Y?

OpenStudy (experimentx):

x*y = 512, x=y, find x and y first.

OpenStudy (anonymous):

How?

OpenStudy (experimentx):

solve those two equations/

OpenStudy (anonymous):

Which equations? Can you give me detailed solution?

OpenStudy (experimentx):

let x be cardinality of set X and y be of cardinality of Y the no of possible realtions = cartesian product, x*y = 512 since they are bijective, x = y

OpenStudy (experimentx):

find the value of x and y.

OpenStudy (anonymous):

I got x = y = 22.62 then? number of elements will be?

OpenStudy (experimentx):

Oo .. there must be some error. it must be an integer, are you sure it's 512??

OpenStudy (anonymous):

Yes!!

OpenStudy (experimentx):

you have the answer??

OpenStudy (anonymous):

No

OpenStudy (anonymous):

any answer for this?

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