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OpenStudy (anonymous):
Its a continuity question. I'm having problem of finding the 'a'.
Question, is
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OpenStudy (anonymous):
\[\tan ax / \tan bx = 4\]given b =4
OpenStudy (anonymous):
\[\tan ax \over \tan bx \]
OpenStudy (anonymous):
@Rohangrr oh yea, the question is to find 'a'.
OpenStudy (anonymous):
Are you sure there are no limits ??
OpenStudy (anonymous):
yes there is, limit is x < 0
do you want me to give the exact question? because this one i already simplify it
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OpenStudy (anonymous):
PLease do give the exact question
OpenStudy (anonymous):
tan(ax )= tan(bx) implies that ax=kPi +bx
maybe this helps...
OpenStudy (anonymous):
ok got it :)
OpenStudy (anonymous):
a=16
OpenStudy (anonymous):
Using this property
\[\lim_{x \rightarrow 0} tanx /x =1 \]
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OpenStudy (anonymous):
yes a=16
@shivam_bhalla , so the after step is?
OpenStudy (anonymous):
Sorry the answer is a= 16
The question is
limit x->0 (tan ax) / (ax) * (bx) / (tan bx) * (ax)/(bx) = 4
now
limit a* x->0 (tan ax) / (ax) = 1
limit b* x->0 (tan bx) / (bx) = 1
Therefore
1*1* ax/bx=4
a/b=4
a= 16
OpenStudy (anonymous):
Sorry for deleting posts so many times :P
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