Question

what is a quadratic function in the form of y = ax2 + bx + c that would have the given roots?

1. x = 2i and x = –2i
2. x =3 + i and x = 3 – i

Answer 1

hint.

Answer 2

quaderatic equation with roots alpha and beta

Answer 3

can be written as (x-alpha)(x-beta)=0

Answer 4

1- (x+2i)(x-2i) = x^2 -4i^2

= x^2 +4

2- (x- (3+i)) (x- (3-i)) = x^2 + (3+i)(3-i)

= x^2 + (9 -i^2) = x^2 - 9

Answer 5

1)
(x-2i)(x+2i)
Multiply it out:
x^2 + 2ix - 2ix - 4i^2
Simplify:
x^2+4

If you really need a, b, and c in there:
y = 1x^2 + 0x + 4


2)
[x-(3+i)][x-(3-i)]
Multiply it out:
x^2 - (3-i)x - (3+i)x + (3+i)(3-i)
x^2 - 6x - ix + ix + 9 - 3i + 3i - i^2
Simplify:
x^2 - 6x + 9 + 1
x^2 + 6x + 10
y = 1x^2 + 6x + 10

this is my answer but i think i did it wrong -___-

Answer 6

The first one is right as I get the same answer but the second one I guess I did something wrong
I think you're right in the second one

Answer 7

@julieteatsyou