Question

Prove the identity tan^2 u(1+cos 2u)=1-cos 2u

Answer 1

Rewrite what with only sin x and cos x?

Answer 2

I just put the rest up there

Answer 3

2sinxcosx + sinx
=sinx( 2cosx + 1)

Answer 4

\[\cos ^{2}x -\sin ^{2}x +sinx\]

Answer 5

Beketso, you mixed up cos 2x with sin 2x =P. Good job Myko! :)

Answer 6

1+2sin^2x+sin x im lost very

Answer 7

oh.pardom me

Answer 8

np

Answer 9

\[1-2\sin ^{2}x+sinx\]

Answer 10

Thank you so much

Answer 11

\[\cos 2x = \cos^2 x - \sin^2 x, \sin^2 x + \cos^2 x = 1\]\[\sin^2 x = 1 - \cos^2 x, \cos^2 x = 1 - \sin^2x\]
\[\cos 2x + \sin x = \cos^2 x - \sin^2 x + \sin x \]\[\cos 2x + \sin x = (1 - \sin^2 x) - \sin^2 x + \sin x = 1 - 2\sin^2 x + \sin x\]

Answer 12

Prove the identity cos(x)/sec(x)-1 - cos(x)/sec(x)+1=2 cos(x)/tan^2(x)

Answer 13

Prove the identity tan^2 u(1+cos 2u)=1-cos 2u

Answer 14

Prove the identity tan^2 u(1+cos 2u)=1-cos 2u