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how do you factor trig. trinomials
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You can look at sin(x) as just being x, and factor that way, then change it back when you're done. Don't forget that \[\sin^2(x)=(\sin(x))^2\] it just looks funny.
so if u had 2sin^2x-sin x-1=0 would this be factorable
Yes, because it's the same as 2x^2-x-1 except that instead of x's you have sin(x)'s instead.
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