Question

solving systems of equations
solve algebraically,
y-x^2=3x
y=x-1

Answer 1

so what is ur question

Answer 2

never mind

Answer 3

\[y=x^2+3x\]
\[y=x-1\] same y, so
\[x^2+3x=x-1\] or \[x^2+2x+1=0\]
\[(x+1)^2=0\] etc

Answer 4

thats not what the answer is meant to be. I think either substitution or elimination is supposed to be used. the answer should be two numbers

Answer 5

that is algebraic

Answer 6

and there are not two solutions, \((-1,-2)\) is the only solution

Answer 7

it is two numbers, namely the x and the y, but it is one solution

Answer 8

where did those 2 numbers come from?

Answer 9

what is x if \((x+1)^2=0\) ?

Answer 10

-1 and 1 not 2?