Question

Find the indefinite integral.

Answer 1

\[\int\limits_{?}^{?}xsin3x^2dx\]

Answer 2

so if i were using u substitution u = 3x^2??

Answer 3

du/dt=6x??

Answer 4

an du/6=xdx?

Answer 5

Yes you are right @ChrisV

You get
\[\int\limits_{}^{} \sin (u) du = -\cos (u) +C\]
\[-\cos(u) +C = -\cos(3x^2 / 2) +C\]

Answer 6

i tend to solve for dx outright; du/6x = dx and when you sub it in the xs cancel regardless

Answer 7

I forgot to divide the answer by 6

Answer 8

And also it is only 3x^2 and not 3x^2/2 . Sorry :P

Answer 9

-1/6cos3x^2 +c

Answer 10

?

Answer 11

Yes you are right @ChrisV