Mathematics
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OpenStudy (anonymous):
The line y=3x+7 is tangent to the graph y=f(x)at x=4. What is f(4)? What Is f′(4).
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OpenStudy (anonymous):
okay let's have some fun.
OpenStudy (anonymous):
f(x) = 7x - x^2
f'(x) = 7- 2x
7- 2x=3
2x= 4
x=2
y = 7x - x^2
y = 14 - 4
y = 10
slope = 3, point (2, 10)
y - y1 = m(x - x1) >> slope point equation of the line.
y -10 = 3(x - 2)
y = 3x - 6+10
y= 3x + 4
OpenStudy (anonymous):
looks like he got it
OpenStudy (tommo_lcfc):
Please explain. Thanks.
OpenStudy (anonymous):
which is f(4) and f'(4)?
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OpenStudy (anonymous):
and how did yo uget your first equation? antiderivative?
OpenStudy (anonymous):
nvm
OpenStudy (anonymous):
still an explanation would be nice
OpenStudy (anonymous):
u need it?
OpenStudy (anonymous):
i'll run you through again okay?
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OpenStudy (anonymous):
give me a medal :]
OpenStudy (anonymous):
yes plz!
OpenStudy (anonymous):
y=3x+7 is tangent to the graph y=f(x) @ x=4. What's f(4)? What's f'(4)?
OpenStudy (anonymous):
y-f(x)=f'(x)(x-a)
OpenStudy (anonymous):
a=4, f(x)=unknown, f'(x)=unknown
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OpenStudy (anonymous):
tangent of graph is found by the formula above
OpenStudy (anonymous):
3x+7=f'(x)(x-a)+f(x)
OpenStudy (anonymous):
tangents have m=-1xrecipricol
OpenStudy (anonymous):
so f(x)=-1/3x+c
OpenStudy (anonymous):
plug in point x=4
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OpenStudy (anonymous):
-1/3(4)+c=f(x)
OpenStudy (anonymous):
c being 7?
OpenStudy (anonymous):
or what is c?
OpenStudy (anonymous):
hmm let me do this on paper, i'll refine it
OpenStudy (anonymous):
ahh...you need to integrate
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OpenStudy (anonymous):
easy
OpenStudy (anonymous):
dirty tricksters as I thought.... then f'(4) is just 19 right?
OpenStudy (anonymous):
y=19
OpenStudy (anonymous):
it's tricky, i'll show you
OpenStudy (anonymous):
wups did you mean integrate the function you found?
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OpenStudy (anonymous):
ahh kk
OpenStudy (anonymous):
@ x=4, y=19
OpenStudy (anonymous):
so you plug that into the integral of tangent
OpenStudy (anonymous):
and find intercept (c)
OpenStudy (anonymous):
c= -33
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OpenStudy (anonymous):
how is it -33?
OpenStudy (anonymous):
henceforth, \[f(x)=3/2x^2+7x-33\]
OpenStudy (anonymous):
at the point x=4, y=19 right?
OpenStudy (anonymous):
the tangent is essentially the line of the gradient m or dy/dx
OpenStudy (anonymous):
at that given point (4,19)
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OpenStudy (anonymous):
so the line is the integral of the tangent at that point true?
OpenStudy (anonymous):
wait..
OpenStudy (anonymous):
it's messy when you have too many unknowns
OpenStudy (anonymous):
yes i was correct
OpenStudy (anonymous):
okay all the answers:
\[f(x)=3/2x^2+7x-33\]
f(4)=639
f'(4)=19
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OpenStudy (anonymous):
i overcomplicated things a lot sorry