Question

could sumone help me ?

Answer 1

Solve the system of linear equations below.


4x - 3y = 17
5x + 4y = 60

Answer 2

can i use a matrix ?

Answer 3

to tell you tha truth idk ?

Answer 4

\[\left(\begin{array}{ccc}4 & -3 \\5 & 4 \end{array}\right) \left(\begin{array}{ccc}x \\y \end{array}\right)
=\left(\begin{array}{ccc}17 \\60 \end{array}\right)\]
If this isnt the method you are expected to use to i dont want to confuse you

Answer 5

A. x = 2, y = -3 B. x = 5, y = 8 C. x = 8, y = 5 D. x = -8, y = -5

Answer 6

or you could just solve it by elimination method, solve for y in the first equation plug it inyour second equation to get x=17 and then sub this number back into your first equation to get y=60

Answer 7

i could tell you the answer but that would be cheating

Answer 8

or if you are entirely lazy you could just try entering the values in each solution (A,B,C,D) into the equations as see if they work or not

Answer 9

NB x≠17, y≠60

Answer 10

or multiply the first equation by 5
\[4x - 3y = 17\qquad\rightarrow 20x-15y=85\]
and the second by 4
\[ 5x + 4y = 60\qquad\rightarrow 20x+16y=240\]
now take away one from the other to cancel the x's

Answer 11

\[-31y=-155\]

Answer 12

and solve for y,

last substitute this value for y into the first(or the second) equation and solve for x