Question

Simplify this expression: 1/tan^2x + cotx tanx

I tried to simplify it and came up with 2+tan^2x. Does that seem right to anyone?

Answer 1

no... it should be cos^2 x

Answer 2

cosec^2x is the answer

Answer 3

+cotx tanx is wid tan^2x ?? like in denominator?

Answer 4

Interesting...how did you both arrive there? I'll try at it to see....

Answer 5

see cotx tanx= tanx/tanx=1
now.. 1/(tan^2x+1)=1/(sec^2x)= cos^2x

Answer 6

No, +cotx tanx is seperate.

Answer 7

so its cot^2x+1 = cosec^2x

Answer 8

1/tan^2x +1
1+tan^2x/tan^2x
sec^2x/tan^2x

cosec^2x

Answer 9

So then it simplies to cosxsec^2x?

Answer 10

OK now I'm getting that it equals 1......1/tan^2x + cotxtanx. Then 1/tan^2x + 1. Then, 1/tan^2x +tan^2x/tan^2x, equals 1+tan^2x/tan^2x, which simplifies to 1.

Answer 11

Is this your problem?\[\frac {1}{\tan^2x} + \cot x \tan x\]If so, that's csc^2 x.

Answer 12

\[\frac {1}{\tan^2x} + \cot x \tan x = \cot^2 x + 1 = \csc^2 x\]

Answer 13

Yeah, that's my problem @Rogue ! I see now, that makes sense!

Answer 14

Glad I could help =)

Answer 15

:)