Question

Could somone help me with this one Algebra1 problem?


8 + x - 1 over x + 4



Thank you!!!!

Answer 1

\[\frac{8+x-1}{x+4}=\frac{7+x}{x+4}\] not much else you can do with it

Answer 2

the eight is by itself its next to the x-1 and thank you

Answer 3

\[8+\frac{x-1}{x+4}=\frac{8(x+4)+x-1}{x+4}=\frac{8x+32+x-1}{x+4}=\frac{9x+31}{x+4}\]

Answer 4

yeah that the right one

Answer 5

hope the steps are clear

Answer 6

They are Thank you @satellite73