need help with simplifying 5x+4/x2-64+3/x-8
so this problem reads (5x+4/x^2) - (64+3/x-8)
\(\large \frac{5x + 4}{x^2 - 64} + \frac{3}{x-8} = \frac{5x+4}{(x+8)(x-8)} + \frac{3}{x-8}\) based from that..can you identify the LCD? remember that the LCD must contain BOTH denominators of both fractions
(5x+4/x^2-64)+(3/x-8)
so the LCD is x-8
Well, you can simplify x^2-64. Do you have an idea how?
like i said the LCD must contain BOTH denominators...since x - 8 does NOT contain x + 8 which is part of the first denominator.. x - 8 is NOT the LCD
you can make that 5x+4/(x-8)(x+8)
Yep, so your problem now looks like [5x+4/(x-8)(x+8) + (3/x-8)] do you know how to cancel out things that are similar on top and bottom?
yeah but you can't cancel anything out there
Good. So what is missing that the denominatours aren't the same?
x+8 isn't in the 2nd one
So you must multiply the numorator and denominatour by x+8 so they are even
how would that read?
that would read 3(x+8)/(x-8)(x+8)
Then you would simplify the top portion
okay, so then you just cancel the demoninators?
first simplify 3(x+8)
3x+24
yes. So now your bottoms are even, you can ignore those. just look at the numerators. What does your problem look thus far?
would the final answer be 4(2x+7)?
5x+4+3x+24 is what your next step would be. If you simplified those, you would get 8x+28. take the 4 so it would be 4(2x+7), so correct!
yes! new favorite web site
I know! I was so amazed when I found this place :D You understand it, right? (the problem, that is)
yeah that really helped now i just have to post 1 more queestion lol
lol maybe I'll help you on there too, but I think your good to close this question!
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