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Solve the boundary-value problem y^2 + 2y^1 + y = 0, y(0) = 1, y(1) = 3 can anyone help me solve this question ??
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nice name n cute pic! here we go y = (Ax+B)e^(-x) , and use 2 conditions to find A , B
are u sure Ax not Bx ? btw, thank you . :)
they probably meant bx
ohh okay, thank you
:D no problem
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yeayyy,.. hihi
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