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Use the quadratic formula to find the zeros of the function. Round to tenths if necessary. y = 17x2 - 21
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in this question you have a = 17, b = 0 and c = -21 the formula is \[x=\frac{-b \pm \sqrt{b^4 - 4ac}}{2a}\] substitute the values and then evaluate to find the zeros
I have tried and always get the wrong answer
what did you get?
1.6 Not sure what im doing wrong
after substituting you should get \[x =\frac{ 0 \pm \sqrt{0^2 - 4\times17\times-21}}{2\times17}\] this simplifies to \[x =\frac{ \pm \sqrt{1428}}{34}\] which can be simplifed
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btw, that should be a b^2 in that radical in your first post...
oops... ty
didn't matter here anyway... :)
would it be 1.1?
yes.... thats the approximation
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