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7.7^(4x + 3) = 10.2
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i love your log questions
lol y?
helps me revise for my exam lol
@hi nyan We have \[\huge 7.7^{(4x+3)}=10.2\] Apply log to both sides what do you get ?
cool so we re helping eachother
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I'll give you a hint \[\large \log a^x=x\log a\]
4x+3=log10.2/log7.7
get 3 to the other side... :P
^after you perform the exponent rule
-0.065
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?
no
do it again
-0.465 sorry dyslexia
\[\LARGE \frac{\log(a)}{\log(b)}=\log_b(a)\]
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yes that's right nyan
lol dyslexia XD
dyslexiz for the win!
one medal for you nyan :D
yay
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