Binomial Distribution help please:: n = 10, p = 0.34, q = 0.66, and x= 0. What is P(0)? (round to the nearest thousandth) I know we can use the compliment rule: P(x2)=P(x is less than or equal to 2). To find the probability that P is at most 2, we need to find the sum of P(0), and P(1). My problem is that I am able to do any other number, but have not been able to figure how to calculate P(0). I know the formula goes something like 10 lower left of capital C and 0 lower right of the capital C = n!/(10-0)!0! =___?____(0.34)^0(0.66)^10....

Question

Binomial Distribution help please::  n = 10, p = 0.34, q = 0.66, and x= 0.   What is P(0)? (round to the nearest thousandth)  I know we can use the compliment rule: P(x>2)=P(x is less than or equal to 2). To find the probability that P is at most 2, we need to find the sum of P(0), and P(1). My problem is that I am able to do any other number, but have not been able to figure how to calculate P(0). I know the formula goes something like 10 lower left of capital C and 0 lower right of the capital C = n!/(10-0)!0! =___?____(0.34)^0(0.66)^10....

anonymous · Answer

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