using the graph h=-0.002d^2 + 0.4d where h is the height of the ball, in mwtres, and d is the distance the ball travels, in metres, until it first hits the ground what is distance does the ball travel horizontally until it first hits the ground
what do you think will be the height of the ball when it hits the ground?
i.e. what will 'h' equal when the ball hits the ground?
i still dont understand all i know is you have to find the perfect square first
do you need the whole question to answer it ?
'h' represents the height of the ball from the ground - correct?
yes
so, what do you think 'h' will be when the ball hits the ground?
actually i have a better question if you have an equation h= -0.0425d^2 + 3.75d at a horizontal distance of 20m from the vertex, what is the height of the arch, to the nearset tenth the horizontal distance is d and h is the height the question is talking about a arch
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