A boy has 11 coins in dimes and quarters. Their value is $1.70. How many of each does he have?

Which of the following equations could be used to solve the problem?
x + (11 - x) = 1.70
25x + 10(11 - x) = 1.70
0.10x + 0.25(11 - x) = 1.70

Question

A boy has 11 coins in dimes and quarters. Their value is $1.70. How many of each does he have?

Which of the following equations could be used to solve the problem?
x + (11 - x) = 1.70
25x + 10(11 - x) = 1.70
0.10x + 0.25(11 - x) = 1.70

anonymous · Answer

i belive the middle one becaue you would want to see how many quarters you can have befor the amount ou dimes i could solve it but my method is diff then the options

anonymous · Answer

Convert dime and quarter into cents 
=> Total = 170 cents

anonymous · Answer

id say 6 quarters to equal 1.50 then add 2 dimes = 1.70

anonymous · Answer

vote me best answer please :)