Question

Once canned Juice drink is 25% orange juice; another is 5%. How many liters of each should be mixed together in order to get 20L that is 22% orange Juice?

Answer 1

25% orange juice; let it be x liters
another is 5%orange juice. this will be 20-x liters
20L that is 19% orange juice
...
0.25x+0.05(20-x) = 0.19*20
0.25x+1-0.05x=1.8
0.20x=1.8-1
0.20x=0.8
x=4 liters of 25% juice
16 liters of 5% juice

Answer 2

Ratio=\(17:3 \implies \) 17 L and 3 Liters of 25% and 5% respectively.

Answer 3

Classic system of equations problems. Let x be the amount of the 25% juice drink; y will be the amount of 5% juice drink. We get two equations

x + y = 20
.25x + .05y = .22(20)

Answer 4

If you convert the second to fractions, and multiply by a convenient factor, the system can solve without too much pain, even without a calculator.

Answer 5

This is your final warning @Rohangrr, Please stop copy pasting wrong answers from other source.

Ref: http://www.algebra.com/algebra/homework/equations/Equations.faq.question.351486.html

Answer 6

oh!!! @FoolForMath okay!!! hows that wrong!

Answer 7

@lcombs: @Rohangrr 's answer is wrong for this question.

Answer 8

@Rohangrr: "20L that is 19% orange juice"