parallelogram ABCD, angle A is 3x + 12 and angle B is 132°. Show your work in finding the value of x.
Hint: Adjacent angles of a parallelogram are supplementary.
Do not give the answer.
Anyone giving answers will be abuse reported.
think: 180-132=? ?=3x+12 ?-12=3x now try to solve it
Really hero.... and 6x?
2nd Hint: Angle A + Angle B = 180 (3x + 12) + 132 = 180
that's what i said...
was it 6? no one told me.....if i was right or wrong...
@RiyaMoon, use the information I just gave you to solve and use algebra.
i jsut freaking did and i get six....
What I mean is, show your steps here.
Actually type them out
urg you divide 12 by three and get 2...then the anwser is two.
nvmforget what i just said. x= 4 so plug 4 in for x and you get 180
3rd Hint: x does not equal 4
x=12 then....
Finally :D
Exemplary work Hero!
180-132=48 3x+12=48 subtract 12 on both sides so it would be 3x=36 divide by 3 on both sides getting x=12..........
Good job, but it would have been better to have written your solution this way: Angle A + Angle B = 180 (3x + 12) + 132 = 180 3x + 12 + 132 = 180 3x + 144 = 180 3x - 144 = 180 3x = 180 - 144 3x = 36 x = 36/3 x = 12 Doing it that way would have shown that you understand that the angles are supplementary and that they have to both add to get a sum of 180.
so...you just gave the answer...
Yes, after providing adequate hints and explanations. But more importantly, I was just clarifying a solution the user had already posted. Did you notice that?
yes...whatever, never mind
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