Question

can 3m^2 + 6mn + 7m + 14 be factored by grouping? how and why?

Answer 1

3m(m+2n) + 7(m+2)

Answer 2

It is because the first two terms have a common factor(3m) and the last also have (7). We can say that we can group the first two and the last two.
3m(m + 2n) + 7(m + 2)

Answer 3

ohhhh, i see where i messed up now

Answer 4

thanks a lot