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Mathematics 15 Online
OpenStudy (anonymous):

how would you graph this ! please help y=(x+1)^2+2

OpenStudy (zepp):

http://puu.sh/s8Y4

hero (hero):

Very helpful @zepp

hero (hero):

She asked "how to graph it" not "what the graph looks like".

OpenStudy (zepp):

:| I'm not sure what do you mean by very helpful

OpenStudy (zepp):

Oh, I misunderstood.

hero (hero):

I get the feeling she doesn't mean graphing with a calculator either.

OpenStudy (zepp):

Pardon me. First find the vertex and plot it on a cartesian plan, y=(x+1)^2+2 The vertex would be (-1, 2)

OpenStudy (zepp):

|dw:1335723930726:dw|

OpenStudy (zepp):

@Hero, don't need to get mad neither :(

hero (hero):

I'm very happy, not mad :)

OpenStudy (anonymous):

thank you both! but i am confused my answer choices don't look the same as the calculator you showed :(

OpenStudy (zepp):

The slope is 1, which is positive, so the parabola should be 'smiling' like Hero.

OpenStudy (zepp):

@aanders, what are the graduation of your cartesian plan? (From your answers)

OpenStudy (zepp):

The graduation of the plan could influence the appearance of the parabola ;D

OpenStudy (anonymous):

rough estimate on the drawings these are the choices |dw:1335724277986:dw|

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