how would you graph this ! please help y=(x+1)^2+2
Very helpful @zepp
She asked "how to graph it" not "what the graph looks like".
:| I'm not sure what do you mean by very helpful
Oh, I misunderstood.
I get the feeling she doesn't mean graphing with a calculator either.
Pardon me. First find the vertex and plot it on a cartesian plan, y=(x+1)^2+2 The vertex would be (-1, 2)
|dw:1335723930726:dw|
@Hero, don't need to get mad neither :(
I'm very happy, not mad :)
thank you both! but i am confused my answer choices don't look the same as the calculator you showed :(
The slope is 1, which is positive, so the parabola should be 'smiling' like Hero.
@aanders, what are the graduation of your cartesian plan? (From your answers)
The graduation of the plan could influence the appearance of the parabola ;D
rough estimate on the drawings these are the choices |dw:1335724277986:dw|
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