Question

find the solutions...
tan x + sec x = 2cosx x[0,2pi]

Answer 1

@Mani_Jha
@Ishaan94
@Zarkon
@experimentX

Answer 2

sinx + 1 = 2 - 2sin^2x

Answer 3

Solve it now.

Answer 4

tan x + sec x = 2cosx
(sinx +1) / cosx = 2cosx
sinx +1 = 2cos^2 x
sinx +1 = 2(1-sin^2x)
2sin^2x +sinx -1 =0
...

Answer 5

i am getting sin x = 1/2 and -1....is it right????

Answer 6

It is

Answer 7

ohhh i forgot...there is a range of the function....the full question has been modified above

Answer 8

sin3pi/2 = -1
sinpi/6 = 1/2

Answer 9

you could also multiply L.H.S. and R.H.S with (secx-tanx)

Answer 10

hmm 3solutions