The sum of three consecutive integers is 267. What is the largest integer?
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OpenStudy (anonymous):
n + n + 1 + n + 2 = 267.
3n + 3 = 267
n = ?
OpenStudy (anonymous):
you can call the integer \(n\) then the next one is \(n+1\) and the one after that is \(n+2\) add to get
\[n+n+1+n+2=267\]
OpenStudy (anonymous):
Largest will be n+2.
OpenStudy (anonymous):
88+2=90 largest
OpenStudy (anonymous):
Sounds good.
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OpenStudy (anonymous):
Although, we were not testing YOU to see if you can figure out from where we left off.
OpenStudy (anonymous):
?
OpenStudy (anonymous):
wait so what was it.......
OpenStudy (anonymous):
lol let one integer x
so consecutive will be one bigger than x= x+1
and other consecutive will be one bigger than x+1=x+2
now sum of these 3 = 267
x+x+1+x+2=267
3x+3=267
3x=264
x=88
now we know that the biggest one is x+2 right? plus in the value of x
88+2=90 which is biggest
OpenStudy (anonymous):
plug in*
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OpenStudy (anonymous):
so its 90? or is it that because its supposed to be a numerical number