Ask your own question, for FREE!
Mathematics 21 Online
OpenStudy (anonymous):

determine whether series converges sum from n=1 to infinity 1/(2n+3)^4 I know it converges but can anyone guide me through the test in which I approach that? Why do I apply the integral test?

OpenStudy (amistre64):

if the ratio and other test are inconclusive; the integral test is a valid option

OpenStudy (amistre64):

since an integration is a larger sum than a discrete summation; if the larger sum converges, the lesser has to

OpenStudy (anonymous):

how would i know the other tests don't work? There are so many. (ratio, p-series, geometric, comparison, etc

OpenStudy (amistre64):

its not a matter of "doesnt work" its a matter of if they come up inconclusive; which I believe has to do with a zero

OpenStudy (anonymous):

Also, maybe a comparison test? Compare with 1/(2n)^4, I think it's possible, or not?

OpenStudy (amistre64):

for example; 1/n limits to zero; but it diverges; so the limit test is inconclusive if the limit = 0

OpenStudy (anonymous):

ah. So how would I work out the problem? replace n's for x's, then use u-substitution u=the inside 2x+3? what do i do with the power 4? Can you carry it out for me?

OpenStudy (anonymous):

so there's more than one way to get the answer?

OpenStudy (amistre64):

if you ned to usub it thats fine ...

OpenStudy (anonymous):

Generally, yes. There are multiple ways :-)

OpenStudy (anonymous):

this whole series and sequence is killing me

OpenStudy (amistre64):

it can be confusing since we have to think in terms of infinity itself

OpenStudy (anonymous):

is there a general rule for each test?

OpenStudy (amistre64):

yes, they tend to be printed in your textbooks .... i cant recall them at the moment tho

OpenStudy (anonymous):

By the way, can we compare with just 1/n^4? Then, it converges because it's a p-series with p > 1. As 1/n^4 >= 1/(2n+3)^4, the original series converges.

OpenStudy (anonymous):

And if you are using Stewart's Calc textbook, there's a cheat sheet on section 11.6, IIRC.

OpenStudy (amistre64):

maybe 1/(2n)^4

OpenStudy (anonymous):

the strategies for series, i know but it doesn't seem to help. I was hoping you guys have a trick that can help you remember :)

OpenStudy (anonymous):

does patrickjmt videos help?

OpenStudy (anonymous):

Think so. I thought they were useful at least. But I watched mostly the Taylors series videos from him

OpenStudy (anonymous):

ok, ill refer to them but I'm just going to hit the books and see what I can do with the example problems.

OpenStudy (anonymous):

Thanks

OpenStudy (anonymous):

No problem. But I think in order to be good at series/sequences you have to do a ton of exercises. It's like integration, you have to acquire some experience. :-)

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!