Question

find the integral of: (3+4x)e^(6x+4x^2)

Answer 1

\(\Large \int (3+4x) e^{(6x + 4x^2)} dx\)

is that the question?

Answer 2

yes, that is correct

Answer 3

have you tried letting u = 6x + 4x^2?

Answer 4

try it :) you'll find the answer :DDD i'll guide you

Answer 5

Hey lgba u r great at it :D Congrats

Answer 6

answer is 1/2 e^(2x(2x+3)) + c

Answer 7

@oj4747 we do not give answers here at openstudy..we try to guide our askers as much as we can

Answer 8

well that's what I thought but it was a complete guess...where do you get the 1/2?

Answer 9

hmmm that from when u did subsitution

Answer 10

like i said let u = 4x^2 + 3x
du = (8x + 6)dx

notice how if you divide both sides by two you get..

du/2 = (8x+6)/2 dx

simplifying...

du/2 = (4x + 3)dx

notice that? so your integral would be

\(\LARGE \int e^u \frac{du}{2}\)

pull out 1/2

\(\LARGE \frac{1}{2} \int e^u du\)

make sense?

Answer 11

makes perfect sense...thanks!