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If this is true, Find (integral problem)
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\[\int\limits_{1}^{3}f(x)dx=5 \] and \[\int\limits_{1}^{3}g(x)dx=7\], find \[\int\limits_{1}^{3}-2f(x)dx-\int\limits_{1}^{3}3g(x)dx\]
hmmm its not turnning into the equation like i still see the language if that makes sense
maybe smth is wrong with my comp
i typed it our in equation i think
substitute in the 5 and 7 to get -2(5)-3(7) and solve
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hmm my comp then
so its -31?
yes, because you can use properties of integrals to bring the coefficients outside the integrand, thus leaving you with what was given at the beginning, su and you just have to substitue
thank you so much
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