Write the slope-intercept equation of the line perpendicular to y = 5/2 x - 2, which passes through the point (0, 2).

Question

zepp · Answer

What would be the slope of a function that's perpendicular to y = 5/2x -2?

anonymous · Answer

5/2

anonymous · Answer

?

zepp · Answer

A slope of a function that's perpendicular to y = 5/2x - 2 would be -2/5 (Change sign, flip the fraction)

zepp · Answer

Now you have $$y=\frac{-2}{5}x$$

anonymous · Answer

oh, ok...

zepp · Answer

To find the y intercept, plug the point into this
$$y = \frac{-2}{5}x+b$$

Plug the point, (0, 2)
$$2 = \frac{-2}{5}0+b$$$$2 = b$$

anonymous · Answer

how do i do this one? Write the equation for the horizontal line passing through (4, -6).

zepp · Answer

Well, you have the slope, now what you need to find is the y-intercept so you can satisfy the condition.

zepp · Answer

Now we know that the y-intercept of this perperndicular function is 2
We put that back, $$y = \frac{-2}{5}x + 2$$