Question

ANYONE WILLING TO HELP??

Answer 1

Let x be the speed he goes by jog
Then the distance would be \[\frac{3}{4}x\]
The speed for bike would be x+9
Then the distance would be \[\frac{1}{3}(x+9)\]

Answer 2

You want to find an x such that \[{x \over {3/4}}+9={x \over {1/3}}\]If x is the distance to work, then \(x\over3/4\) is the speed at which he jogs there, and \(x\over1/3\) is the speed he bikes there. Since he bikes 9mph faster, we add 9 to the left hand side.

Answer 3

If we solve this for x, we get that \[{x \over {3/4}}+9={x \over {1/3}}\]\[{4x \over 3} +9 =3x\]\[9 =3x-{4x \over 3}\]\[9 ={9x \over 3}-{4x \over 3} ={5x \over 3}\]\[27=5x\]\[x={27 \over 5}\]So the distance should be 27/5 miles.

Answer 4

If you want to find his actual jogging/biking speed (you don't have to) then you get that he jogs at 7.2 mph, and bikes at 16.2 mph

Answer 5

So my thing also work :D

Answer 6

@zepp Yeah, but that solves for the velocity first, I think. Maybe I did some arithmetic mistake but I got 7.2 from your way (that was the same as mine :-) )

Answer 7

Jogs at 7.2mph, same as KingGeorge's answer, we're good. :)

Answer 8

So you way might be more complicated, but it works.